**Decimal to binary conversion:**

125

_{10}
125

_{10}=1111101_{2}_{}125.25

_{10}

_{}For decimal part use above procedure of LCM, For fraction part multiply fraction part with 2, from result only take decimal part, and multiply the fraction part of result again by 2. Repeat the same procedure until fraction part is zero or required no. of bit positions after decimal point.

Thus 125.25

_{10}=1111101.01_{2}_{}

**Decimal to octal conversion:**

**1023**

_{10}

1023

_{10 }=1777_{8}_{}

**Decimal to hex-decimal:**

1023

_{10}
1023

_{10}=3FF_{16}_{}

**Octal to binary:**

563

_{8}

_{}**Hex-decimal to binary:**

AF7

_{16}_{}

Represent
each hex-decimal digit with 4-bit binary number

**Binary to octal:**

**111001011010**

_{2}

Partition
data into three bit sets, from right to left. Represent each set with an octal
digit.

**Binary to hex-decimal:**

**1110010101100001**

_{2}

Partition data into four bit sets, from right to
left. Represent each set with a hex-decimal digit.

1110 | 0101 | 0110 | 0001 = E561

_{16}**Any base to any base conversion:**

- Convert given base number into decimal number
- Convert that decimal number into required base

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